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Published byCory Lloyd Modified over 8 years ago
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Uniform Problem A subway train on the Red Line arrives every 8 minutes during rush hour. We are interested in the length of time a commuter must wait for a train to arrive. The time follows a uniform distribution. Let X = the length of time a commuter must wait for the train to arrive, in minutes 0 X 8 X ~ U(0, 8)
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Uniform Problem Graph the probability distribution. a = b = 8
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Uniform Problem f(x) = = =
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Uniform Problem f(x) = = =
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Uniform Problem P(X < 1) = (1 – 0)(1/8) = 1/8
Find the probability that the commuter waits less than one minute. P(X < 1) = (1 – 0)(1/8) = 1/8
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Uniform Problem P(2 < X < 5) = (5 – 2)(1/8) = 3/8
Find the probability that the commuter waits between two and five minutes. P(2 < X < 5) = (5 – 2)(1/8) = 3/8
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Uniform Problem Let k = the 90th %ile 0.90 = (k – 0)(1/8) k = 7.2 min.
Find the 90th percentile. (90% of the wait times are less than this value.) Let k = the 90th %ile 0.90 = (k – 0)(1/8) k = 7.2 min.
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Uniform Problem 0.60 = (8 – k)(1/8) 4.8 = 8 – k k = 3.2
60% of the time the commuter waits more than how long for the train? 0.60 = (8 – k)(1/8) 4.8 = 8 – k k = 3.2
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Uniform Problem P(X > 5 | X > 3) = (8 – 5)(1/5)=3/5
CONDITIONAL: Find the probability that the commuter waits more than five minutes when he/she has already waited more than three minutes. P(X > 5 | X > 3) = (8 – 5)(1/5)=3/5
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