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Published byHeather Hunter Modified over 8 years ago
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Lesson Menu Five-Minute Check (over Lesson 1–3) CCSS Then/Now New Vocabulary Key Concept: Absolute Value Example 1:Evaluate an Expression with Absolute Value Example 2:Real-World Example: Solve an Absolute Value Equation Example 3:No Solution Example 4:One Solution
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CCSS Content Standards A.SSE.1.b Interpret complicated expressions by viewing one or more of their parts as a single entity. A.CED.1 Create equations and inequalities in one variable and use them to solve problems. Mathematical Practices 6 Attend to precision.
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Then/Now You solved equations using properties of equality. Evaluate expressions involving absolute values. Solve absolute value equations.
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Vocabulary absolute value empty set constraint extraneous solution
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Concept
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Example 1 Evaluate an Expression with Absolute Value Answer: 4.7 Replace x with 4. Multiply 2 and 4 first. Subtract 8 from 6. Add.
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Example 1 A.18.3 B.1.7 C.–1.7 D.–13.7
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Example 2 Solve an Absolute Value Equation Case 1a=b y + 3=8 y + 3 – 3=8 – 3 y=5y=5 Answer: The solutions are 5 and –11. Thus, the solution set is –11, 5 . Check|y + 3|=8 Case 2a=–b y + 3=–8 y + 3 – 3=–8 – 3 y=–11 |y + 3|=8 ? |5 + 3|=8 ? |8|=8 8=88=8 ? |–11 + 3|=8 ? |–8|=8 8=88=8
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Example 2 A.{5} B.{–10, 5} C.{–5, 10} D.{–5} What is the solution to |2x + 5| = 15?
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Example 3 No Solution Solve |6 – 4t| + 5 = 0. This sentence is never true. Answer: The solution set is . |6 – 4t| + 5=0Original equation |6 – 4t|=–5Subtract 5 from each side.
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A. B. C. D. Example 3
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Example 4 One Solution Case 1a=b 8 + y=2y – 3 8=y – 3 11=y
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Example 4 One Solution Check: Answer:
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A. B. C. D. Example 4
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