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Topic 1.3 Extended A - Vector Addition and Subtraction
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Unfortunately, objects move. If they didn't, finding the big three would be a cinch. As it is, most of the things we interact with, in fact, we ourselves, move. Topic 1.3 Extended A - Vector Addition and Subtraction And, to make matters worse, we move in more than one dimension. In this section we will look at vectors. A vector is a quantity that has both magnitude (size) and direction.
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Topic 1.3 Extended A - Vector Addition and Subtraction The direction of particle moving along a line is given by either a + sign (moving in the positive direction) or a - sign (moving in the negative direction). Thus, if a particle is traveling at 2 ft/s along the x-axis, it is moving in the positive x-direction. If a particle is traveling at - 8 ft/s along the y- axis, it is moving in the negative y-direction. However, if a particle is moving in the x-y plane, NOT ALONG EITHER AXIS, its direction cannot be given with a simple sign. Instead, we need an arrow to show its direction. Such an arrow is called a vector. A vector has both magnitude (numerical size), and direction. Not all physical quantities have a direction. For example, pressure, time, energy, and mass do not have direction. Non-directional quantities are called scalars. x y x y x y vector
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Topic 1.3 Extended A - Vector Addition and Subtraction The simplest vector is called the displacement vector. The displacement vector is obtained by drawing an arrow from a starting point to an ending point. For example, starting at Milwaukee and ending in Sheboygan would have a displacement vector that looks like this: Note that the displacement vector (black) does not necessarily show the actual path followed (purple). A displacement is simply a directed change in position, with disregard to the route taken. displacement vector actual path Note that the displacement vector traces out the SHORTEST distance between two points. FYI: The displacement from Sheboygan to Milwaukee has the same magnitude. What is different about it?
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Topic 1.3 Extended A - Vector Addition and Subtraction The magnitude (size) of a displacement on the x-y plane is easy to obtain using the Pythagorean theorem or the distance formula: d = (x 2 - x 1 ) 2 + (y 2 - y 1 ) 2 distance formula √ √ √ √ √ √ For example, the displacement shown has a magnitude given by d = (x 2 - x 1 ) 2 + (y 2 - y 1 ) 2 = (5 - 1 ) 2 + (4 - 1 ) 2 = 4 2 + 3 2 = 16 + 9 = 25 = 5 ft. x (ft) y (ft) (x 1, y 1 ) = (1, 1) (x 2, y 2 ) = (5, 4) start end
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Topic 1.3 Extended A - Vector Addition and Subtraction Of course, a scale drawing would allow you to measure the magnitude of the displacement directly with a ruler: x (ft) y (ft) (x 1, y 1 ) = (1, 1) (x 2, y 2 ) = (5, 4) start end Note that the length of the arrow is 5 ft.
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Topic 1.3 Extended A - Vector Addition and Subtraction In print, vectors are designated in bold non-italicized print. Consider two vectors: vector a and vector b. For our purposes, when we are writing a vector symbol on paper, use the letter with an arrow symbol over the top, like this: Each vector has a tail, and a tip (the arrow end). a b tail tip
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Topic 1.3 Extended A - Vector Addition and Subtraction Suppose we want to find the sum of the two vectors a + b = s. We take the first-named vector a, and translate the second-named vector b towards the first vector, SO THAT THE TAIL OF b CONNECTS TO THE TIP OF a. The result of the sum, which we are calling the vector s, is gotten by drawing an arrow from the tail of a to the tip of b. We are giving the sum an arbitrary name - say s. a b tail tip "translate" means to move without rotation. s tail tip
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Topic 1.3 Extended A - Vector Addition and Subtraction We can think of the sum a + b = s as the directions on a pirate map: Arrgh, matey. First, pace off the first vector a. Then, pace off the second vector b. And ye'll be findin' a treasure, aye!
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Topic 1.3 Extended A - Vector Addition and Subtraction We can think of the sum a + b = s as the directions on a pirate map: We start by pacing off the vector a, and then we end by pacing off the vector b. The treasure is at the ending point. a b start end a + b = s s The vector s represents the shortest distance to the treasure.
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Topic 1.3 Extended A - Vector Addition and Subtraction Now, suppose we want to subtract vectors. b -b-b the vector b the opposite of the vector b a -b-b a+-ba+-b a-b = a + -b-b Thus, Just as you learned how to subtract integers by "adding the opposite," so, too, will we subtract vectors. Thus the difference of two vectors a - b is given by a - b = a + - b.difference of two vectors We just have to define the "opposite of b" or " - b." The opposite of a vector is the vector that is the same length, but points in the opposite direction.
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Topic 1.3 Extended A - Vector Addition and Subtraction Observe the addition of vectors is commutative: a + b = b + a c b a (a+b)(a+b) c b a (a+b)+c (b+c)(b+c) a+(b+c) Observe that addition of vectors is associative: (a + b) + c = a + (b + c) b a a b a+ba+b b+ab+a
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Topic 1.3 Extended A - Vector Addition and Subtraction A pirate takes 6 paces east, 4 paces north, 2 paces west, and 1 pace south. (a) Draw a vector diagram showing the pirate's path. (b) How far does the pirate walk? (c) Draw in the displacement vector. (d) What is the magnitude of the displacement? N (pc) E (pc) 6 paces 4 paces 2 paces 1 pace 6 paces 4 paces2 paces1 pace + + + = 13 paces 5 paces
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Topic 1.3 Extended A - Vector Addition and Subtraction Suppose you know a vector's magnitude and direction. opp hyp adj hyp opp adj hypotenuse adjacent opposite θ trigonometric ratios s-o-h-c-a-h-t-o-a θ d d x = d cos θ d y = d sin θ d dxdx dydy d d d x = d cos θ d y = d sin θ sin θ = cos θ = tan θ = dxdx dydy You can find its components using the trigonometric functions:
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Topic 1.3 Extended A - Vector Addition and Subtraction Recall the four quadrants of the Cartesian coordinate system: x(+) x(-) y(+) y(-) I II III IV I++I++ II-+ III-- IV+- Quadrantxy Components will "inherit" the signs of the quadrants. For example, a vector in Quad II will have a negative x-component and a positive y-component. A vector in Quad III will have negative x-component and a negative y-component.
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Topic 1.3 Extended A - Vector Addition and Subtraction Standard angles are measured with respect to the +x-axis in a counter-clockwise rotation: If these angles are used in d x = d cos θ and d y = d sin θ the correct component signs will be automatic. Reference angles are measured with respect to either x(+) or x(-), whichever is smaller. If these angles are used in d x = d cos θ and d y = d sin θ the correct component signs will NOT be automatic. Just use the table on the previous page for the signs of the components. x(+) x(-) y(+) y(-) θ1θ1 θ2θ2 standard angles x(+) x(-) y(+) y(-) θ1θ1 θ2θ2 reference angles
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Topic 1.3 Extended A - Vector Addition and Subtraction 45° Suppose you have a displacement d of 200-m at 135º. Find its components. Using standard angle: d x = d cos θ = 200 cos 135° = - 141.4 m d y = d sin θ = 200 sin 135° = 141.4 m SIGNS AUTOMATIC Using reference angle: d x = d cos θ = 200 cos 45° = 141.4 m d y = d sin θ = 200 sin 45° = 141.4 m SIGNS NOT AUTOMATIC d x is (-), and d y is (+) so that d x = - 141.4 m d y = 141.4 m x(+) x(-) y(+) y(-) 135° standard angle x(+) x(-) y(+) y(-) reference angle 180 ° - 135° = 45 ° d x (-) d y (+) Since the signs are not automatic, sketch in components:
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Topic 1.3 Extended A - Vector Addition and Subtraction Many angles will be given with respect to the points of the compass. Often a compass is divided into 45° increments. Then northeast is precisely 45° between north and east. Sometimes the compass is divided into 22.5° increments. Then we can speak of NNE, and ENE, and assign a precise angle to each. ENE NNE
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Topic 1.3 Extended A - Vector Addition and Subtraction Finally, we can speak of angles such as "30° east of north," which is a reference to an angle drawn 30° from the north direction, in the eastward direction. 30° 30° east of north north Then you can draw your own, exact, right triangle. 30° 60°
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Topic 1.3 Extended A - Vector Addition and Subtraction Consider the two vectors A and B shown below. y (ft) x (ft) A B To add the vectors by components, simply add the x-components, then add the y-components. A x = 3 ft A y = 2 ft B x = - 1 ft B y = - 2 ft R = A + B R x = A x + B x = 3 ft + - 1 ft = 2 ft R y = A y + B y = 2 ft + - 2 ft = 0 ft y (ft) x (ft) Graphically by components R start end R y (ft) x (ft) start end A B R Graphically
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Topic 1.3 Extended A - Vector Addition and Subtraction A vector can also be expressed without an angle, and without a picture. This method is often preferred, because it requires no pictures, and therefore less paper. But, you can always make sketches if it helps. To facilitate this method we have to define unit vectors. Unit vectors have UNIT LENGTH (meaning a length of 1) and NO QUANTITY. For example, we could use the directions N, S, E, and W as unit vectors, and express any vector in terms of these unit vectors. Thus the displacement D 1 of 30 miles to the north would look like this: D 1 = 30 miles N Thus the displacement D 2 of 40 miles to the west would look like this: D 2 = 40 miles W We could also express D 2 in terms of the East unit vector: D 2 = -40 miles E FYI: In fact, for 2D we only need 2 unit vectors, N and E. Then west is -E and south is -N. Then the sum of the vectors D = D 1 + D 2 can be written D = 30 miles N + -40 miles E
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^ Topic 1.3 Extended A - Vector Addition and Subtraction Naturally, we are not pirates, and so we don't use the point of the compass as unit vectors. Physicists instead use the following: x is the unit vector in the +x-direction ^ y is the unit vector in the +y-direction ^ z is the unit vector in the +z-direction ^ Unit Vectors FYI: Some books use i, j, and k for the unit vectors in the x, y, and z- directions. We read x as "ex hat." (Really...) ^ x y z We rarely need 3D, but if we do, here is the standard configuration of the three axes: And here are the unit vectors: x ^ y ^ z Incidentally, they don't have to start at the origin: x ^ ^ y ^ z
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Topic 1.3 Extended A - Vector Addition and Subtraction To see how the unit vectors work, let's redo the a previous problem where we found R = A + B: y (ft) x (ft) A B A =A = R 3x3x ^ x ^ y ^ + 2y (ft) ^ B =B = -1x ^ - 2y (ft) ^ R = 2x ^ + 0y (ft) ^ + FYI: Your book uses x instead of x. We will use the x notation in this class because it is the standard. ^ ^
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