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Network delay Slide 1 What are the boundaries of the Praesideo System bus ??

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Presentation on theme: "Network delay Slide 1 What are the boundaries of the Praesideo System bus ??"— Presentation transcript:

1 Network delay Slide 1 What are the boundaries of the Praesideo System bus ??

2 Network delay Slide 2 NC NON redundant system Fiber length System bus length = Fiber length ÷ 2

3 Network delay Slide 3 Redundant system NC Fiber length

4 Network delay Slide 4 Redundant system NC Fiber length System bus length = Fiber length ÷ 2

5 Network delay Slide 5 Some properties of the MOST network:  Delay in a node (30ºC): 120 nS  Delay in a node (60ºC): 175 nS  Delay in Plastic and Glass fiber: 5 nS/m (=200.000 km/sec)  Total delay in system bus: ~20.9 uS

6 Network delay Slide 6  Nr of nodes : 3 + 1 (NCO + 1x amp)  Delay 4 nodes (30ºC): 4 x 120 nSec = 0.48 uS  Delay for fibers: 20.9 uS – 0.48 uS = 20.42 uS  Max Fiber length: 20.42 uS / 5nS/m = 4084 m  Max System bus length: 4084 m / 2 = 2042 m  Nr of nodes : 3 + 1 (NCO + 1x amp)  Delay 4 nodes (60ºC) : 4 x 175 nSec = 0.7 uS  Delay for fibers: 20.9 uS – 0.7 uS = 20.2 uS  Max Fiber length: 20.2 uS / 5nS/m = 4040 m  Max System bus length: 4040 m / 2 = 2020 m Δ L = 22 mtr ( = 1.1%)

7 Network delay Slide 7  Nr of nodes : 3 + 2 (NCO + 1x amp + 1x CST)  Delay 4 nodes (30ºC): 5 x 120 nSec = 0.6 uS  Delay for fibers: 20.9 uS – 0.6 uS = 20.3 uS  Max Fiber length: 20.3 uS / 5nS/m = 4060 m  Max System bus length: 4060 m / 2 = 2030 m  Nr of nodes : 3 + 2 (NCO + 1x amp + 1x CST)  Delay 4 nodes (60ºC) : 5 x 175 nSec = 0.875 uS  Delay for fibers: 20.9 uS – 0.875 uS = 20.025 uS  Max Fiber length: 20.025 uS / 5nS/m = 4005 m  Max System bus length: 4005 m / 2 = 2003 m Δ L = 27 mtr ( = 1.3%)

8 Network delay Slide 8  Max nr of nodes : 63 (max. addresses possible)  Delay 63 nodes (60ºC): 63 x 175 nS = 11.025 uS  Delay for fibers: 20.9 uS – 11.025 uS = 9.875 uS  Max Fiber length: 9.875 uS / 5 nS/m = 1975 m  Max System bus length: 1975 m / 2 = 988 m  Max nr of nodes : 63 (max. addresses possible)  Delay 63 nodes (30ºC) : 63 x 120 nS = 7.56 uS  Delay for fibers: 20.9 uS – 7.56 uS = 13.34 uS  Max Fiber length: 13.34 uS / 5 nS/m = 2668 m  Max System bus length: 2668 m / 2 = 1334 m Δ L = 346 mtr !! ( = 26%)

9 Network delay Slide 9 Relation number of nodes and system bus length, in one ring System bus length (mtr) Number of nodes 102030405060 1000 2000 70 1000

10 Network delay Slide 10 Relation number of nodes and system bus length, in one ring System bus length (mtr) Number of nodes 102030405060 1000 2000 70 1000

11 Network delay Slide 11 ©Robert Bosch GmbH reserves all rights even in the event of industrial property rights. We reserve all rights of disposal such as copying and passing on to third parties.


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