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Published byAldous Gibbs Modified over 8 years ago
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Gas pressure & volume
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p X V = Constant For example, suppose we have a theoretical gas confined in a jar with a piston at the top. The initial state of the gas has a volume equal to 4.0 cubic meters and the pressure is 1.0 kilopascal. With the temperature and number of moles held constant, weights are slowly added to the top of the piston to increase the pressure. When the pressure is 1.33 kilopascals the volume decreases to 3.0 cubic meters. The product of pressure and volume remains a constant (4 x 1.0 = 3 x 1.33333 ).
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Given below is the experimental data of specific amount of a fixed mass of gas at constant temperature P(atm) volume(cm 3 ) p X V(atmXcm 3 ) p 1 = 1 V 1 = 81 X8 = 8 p 2 = 2 V 2 = 42 X 4 = 8 p 3 = 4 V 3 = 24 X 2 = 8
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Boyle’s Law For a fixed mass of gas, at constant temperature: p V = constant p V = constant p 1 V 1 = p 2 V 2 Or Volume is inversely proportional to pressure V 1/p V 1/p
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Solve An exhaust pump is connected to a flask of volume 100 cm 3. The volume swept out by the piston is 25 cm 3 for each stroke. The pressure in the vessel is originally 1 atm. By considering one stroke at a time, find the pressure in the vessel after two strokes. By considering one stroke at a time, find the pressure in the vessel after two strokes.
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solve A 6 litre container of gas has a pressure of 8.2 atm. i) Calculate the new volume occupied by the gas if the pressure is reduced by 3 atm at the same temperature. ii) What will be the new volume if the pressure is reduced to 4 atm in the given example?
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