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Rank Annihilation Based Methods. p n X The rank of matrix X is equal to the number of linearly independent vectors from which all p columns of X can be.

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Presentation on theme: "Rank Annihilation Based Methods. p n X The rank of matrix X is equal to the number of linearly independent vectors from which all p columns of X can be."— Presentation transcript:

1 Rank Annihilation Based Methods

2 p n X The rank of matrix X is equal to the number of linearly independent vectors from which all p columns of X can be constructed as their linear combination Geometrically, the rank of pattern of p point can be seen as the minimum number of dimension that is required to represent the p point in the pattern together with origin of space rank(P p ) = rank(P n ) = rank(X) < min (n, p) Rank

3 xPxP yPyP Variance P Q R yQyQ yRyR xQxQ xRxR x y O x P y P x Q y Q x R y R OP 2 = x P 2 + y P 2 OQ 2 = x Q 2 + y Q 2 OR 2 = x R 2 + y R 2 OP 2 + OQ 2 + OR 2 = x P 2 + y P 2 + x Q 2 + y Q 2 + x R 2 + y R 2 Sum squared of all elements of a matrix is a criterion for variance in that matrix

4 Eigenvectors and Eigenvalues For a symmetric, real matrix, R, an eigenvector v is obtained from: Rv = v is an unknown scalar-the eigenvalue Rv – v  = 0 (R – I  v  = 0 The vector v is orthogonal to all of the row vector of matrix (R- I) Rv = v0v - RI =

5 Variance and Eigenvalue 2 4 3 6 D = 1 2 Rank (D) = 1 Variance (D) = (1) 2 + (2) 2 + (3) 2 + (2) 2 + (4) 2 + (6) 2 = 70 Eigenvalues (D) = [70 0] 4 2 3 6 D = 1 2 Rank (D) = 2 Variance (D) = (1) 2 + (4) 2 + (3) 2 + (2) 2 + (2) 2 + (6) 2 = 70 Eigenvalues (D) = [64.4 5.6]

6 Free Discussion The relationship between eigenvalue and variance

7 10 uni-components samples Eigenvalues (D) = 204.7 0 Without noise 204.6 0.0012 0.0011 0.0009 0.0008 0.0006 0.0005 Eigenvalues (D) = with noise

8 10 bi-components samples Eigenvalues (D) = 262.65 18.94 0 Without noise Eigenvalues (D) = with noise 262.64 18.93 0.0011 0.0009 0.0008 0.0007 0.0006 0.0005

9 Bilinearity As a convenient definition, the matrices of bilinear data can be written as a product of two usually much smaller matrices. D = C E + R =

10 Bilinearity in mono component absorbing systems

11 =

12 =

13 =

14 =

15 =

16 =

17 =

18 =

19 =

20 =

21 =

22 =

23 =

24 =

25 =

26 Bilinearity in multi-component absorbing systems A B C k1k1 k2k2 D = C S T D = c A s A T + c B s B T + c C s C T

27 sATsAT cAcA cA sATcA sAT Bilinearity

28 sBTsBT cBcB cB sBTcB sBT

29 sCTsCT cCcC cC sCTcC sCT

30 cA sATcA sAT cB sBTcB sBT cC sCTcC sCT ++

31 Spectrofluorimetric spectrum Excitation-Emission Matrix (EEM) is a good example of bilinear data matrix Excitation wavelength Emission wavelength EEM

32 One component EEM

33 Two component EEM

34 Free Discussion Why the EEM is bilinear?

35 C=1.0 C=0.8 C=0.6 C=0.4 C=0.2 Trilinearity

36 Quantitative Determination by Rank Annihilation Factor Analysis

37 Two components mixture of x and y C x =1.0 and C y =2.0

38 Two components mixture of x and y

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52 - = C x =1.0 C y =2.0 C x =0.4 C y =0.0 Residual Two components mixture of x and y

53 C x =1.0 C y =2.0 C x =1.5 C y =0.0 Residual - = Two components mixture of x and y

54 C x =1.0 C y =2.0 C x =1.0 C y =0.0 Residual - = Two components mixture of x and y

55 Mixture StandardResidual - = M – S = R Rank(M) = nRank(S) = 1 Rank(R) = n n-1 Rank Annihilation

56 The optimal solutions can be reached by decomposing matrix R to the extent that the residual standard deviation (RSD) of the residual matrix obtained after the extraction of n PCs reaches the minimum  j=n+1 c j n (c– 1) ( ) RSD(n) = 1/2

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58 RAFA1.m file Rank Annihilation Factor Analysis

59 Saving the measured data from unknown and standard samples

60 Calling the rank annihilation factor analysis program

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62 Rank estimation of the mixture data matrix

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68 ? Use RAFA1.m file for determination one analyte in a ternary mixture using spectrofluorimetry

69 Simulation of EEM for a sample

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80 ? Investigate the effects of extent of spectral overlapping on the results of RAFA


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