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Published byBruno Clyde King Modified over 9 years ago
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Pythagoras Theorem Proof of the Pythagorean Theorem using Algebra
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We can prove that a 2 + b 2 = c 2 There are four ‘abc’ triangles in this figure The big square formed by these triangles has a side a+b
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Total area of the big square is A=(a+b)(a+b) The area of the smaller square (inside the big one) is A= c 2
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The area of a triangle is A =½ab
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The area of four triangles together is A = 4(½ab) = 2ab
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So the area of the four triangles and the small square is A = c²+2ab
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The area of the big square is equal to the area of the small square and four triangles So we have (a+b)(a+b)= c²+2ab a 2 +2ab+ b 2 = c²+2ab Subtract ‘2ab’ in both sides and we have a 2 + b 2 = c 2
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Pythagoras Theorem 2 nd Proof
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β c - bb c c S OR Q P yx a α P P RS R Q P S Q α α β β x y a a c + b 2c x y
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