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Pythagoras Theorem Proof of the Pythagorean Theorem using Algebra.

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Presentation on theme: "Pythagoras Theorem Proof of the Pythagorean Theorem using Algebra."— Presentation transcript:

1 Pythagoras Theorem Proof of the Pythagorean Theorem using Algebra

2 We can prove that a 2 + b 2 = c 2 There are four ‘abc’ triangles in this figure The big square formed by these triangles has a side a+b

3 Total area of the big square is A=(a+b)(a+b) The area of the smaller square (inside the big one) is A= c 2

4 The area of a triangle is A =½ab

5 The area of four triangles together is A = 4(½ab) = 2ab

6 So the area of the four triangles and the small square is A = c²+2ab

7 The area of the big square is equal to the area of the small square and four triangles So we have (a+b)(a+b)= c²+2ab a 2 +2ab+ b 2 = c²+2ab Subtract ‘2ab’ in both sides and we have a 2 + b 2 = c 2

8 Pythagoras Theorem 2 nd Proof

9 β c - bb c c S OR Q P yx a α P P RS R Q P S Q α α β β x y a a c + b 2c x y


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