Download presentation
Presentation is loading. Please wait.
Published byWesley Carson Modified over 9 years ago
4
LargerScientistsUnits e- config 101 Is it possible? Potpourri $ 200 $ 200$200 $ 200 $ 200 $400 $ 400$400 $ 400$400 $600 $ 600$600 $ 600 $ 600 $ 600 $800 $ 800$800 $ 800 $ 800 $ 800 $ 1000$1000 $ 1000 $ 1000 $ 1000 $ 1000
5
Smaller So many rules Trends e- config 201 Quantum #More #s $ 400 $ 400 $ 400 $ 400 $ 400 $ 400 $ 800 $ 800 $ 800 $ 800 $ 800 $ 800 $ 1200 $ 1200 $ 1200 $ 1200 $ 1200 $ 1200 $ 1600 $ 1600 $ 1600 $ 1600 $ 1600 $ 1600 $ 2000 $ 2000 $ 2000 $ 2000 $ 2000 $ 2000
6
Final Jeopardy Using the Equations
7
Final Jeopardy 3.77 * 10 -19 J A photon of green light has a wavelength of 525nm. Calculate the energy of the photon (in J).
8
$200 Si Larger Atomic radius of Si or Cl
9
$400 red Larger λ of red light or green light
10
$600 green Larger ν of red light or green light
11
$800 radio Larger λ of radio waves or γ rays
12
$1000 Ionic radius of O 2- Larger atomic radius of O or ionic radius of O 2-
13
$200 Mendeleev
14
$400 Bohr
15
$600 Einstein
16
$800 Schrödinger
17
$1000 Heisenberg
18
$200 m or nm λ
19
$400 Hz or 1/s or s -1 ν
20
$600 J E
21
$800 m/s c
22
$1000 J*s h
23
$200 Li 1s 2 2s 1
24
$400 1s 2 2s 2 2p 2 C
25
$600 Al [Ne] 3s 2 3p 1
26
$800 Br [Ar] 4s 2 3d 10 4p 5
27
$1000 Sg [Rn] 7s 2 5f 14 6d 4
28
$200 Yes 4 3 -2 +½
29
$400 No (m s can only be +½ or -½) 4 3 -2 1
30
$600 Yes 2 0 +½
31
$800 Yes 3 2 -½
32
$1000 No (l values range from 0 to n-1) 2 1 +½
33
$200 anion The name for a negative ion
34
$400 6 S has this # of valence e-
35
$600 2+ Ca ions have this charge
36
$800 Wave-like and particle-like (matter) Light can exhibit a duality of these two properties
37
$1000 Quanta Planck identified that energy comes in packets called what?
38
$400 Ca Smaller electronegativity O or Ca
39
$800 p (3 orientations vs. f with 7 possible orientations) Smaller possible # of orientations p or f shaped orbital
40
$1200 K (require less E to remove outer e- b/c more n, more shielding, further from nucleus) Smaller ionization energy Na or K
41
$1600 n = 5 to n = 6 Smaller energy required to excite an e- from n = 2 to n = 3 or from n = 5 to n = 6
42
$2000 O 2- Smaller ionic radius N 3- or O 2-
43
$400 Pauli Exclusion Principle This tells us no 2 e- in the same atom have the same E (or the same set of quantum numbers)
44
$800 Aufbau Principle This tells us that e- fill orbitals in increasing order of energy
45
$1200 Hund’s Rule This tells us the lowest energy is attained when # of e- with the same spin is maximized
46
$1600 Cr This element is an exception to the rule as it attains greater stability with a ½ filled d subshell and ½ filled s subshell than with its expected 4s 2 3d 4 configuration
47
$2000 Emission spectra / line spectra Rule: We can use this type of spectra to identify an element because no two will be the same
48
$400 More protons, greater nuclear charge This explains why atomic size decreases as we move from left to right across a period
49
$800 More n, greater shielding effect, larger n further away from nucleus This explains why ionic radius increases as we move down a group
50
$1200 Electronegativity This trend tells us an element’s ability to attract e-
51
$1600 Ionization Energy/ Potential This trend tells us the amount of energy required to remove an e- from an atom
52
$2000 Bottom Left This corner of the periodic table includes elements that exhibit the greatest metallic characteristics
53
$400 ns 2 np 6 The general e- config. for a noble gas
54
$800 ns 2 np 2 The general e- config. for an element in Group 4A
55
$1200 [Ne] The noble gas configuration of F - ion
56
$1600 Alkali earth metals An element with the general configuration ns 2 is part of which group (specific name please)
57
$2000 Actinoids An element with the configuration [Rn]7s 2 5f 12 is found in this series of elements
58
$400 l Tells us the shape of an orbital
59
$800 n Describes the energy level or size of an orbital
60
$1200 msms Tells us the spin of an e-
61
$1600 mlml Tells us orientation in space of a given orbital
62
$2000 -3, -2, -1, 0, 1, 2, 3 These are the possible values for m l when l = 3
63
$400 2 Maximum # of e- per orbital
64
$800 8 (2 in the s orbital + 6 in the p orbitals) Maximum # of e- in n = 2
65
$1200 5 # of d orbital orientations
66
$1600 4 (s, p, d, and f) Possible # of subshells in n = 4
67
$2000 8 (2 in 1s + 2 in 2s + 2 in 3s + 2 in 4s) # of e- in the s orbitals of a Ca atom
68
Daily Double Yes 2 0 +½
69
Daily Double n = 5 to n = 6 Energy required to excite an e- from n = 2 to n = 3 or from n = 5 to n = 6
70
Daily Double More n, greater shielding effect, larger n further away from nucleus This explains why ionic radius increases as we move down a group
71
The Jeopardy champion!
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.