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LargerScientistsUnits e- config 101 Is it possible? Potpourri $ 200 $ 200$200 $ 200 $ 200 $400 $ 400$400 $ 400$400 $600 $ 600$600 $ 600 $ 600 $ 600.

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Presentation on theme: "LargerScientistsUnits e- config 101 Is it possible? Potpourri $ 200 $ 200$200 $ 200 $ 200 $400 $ 400$400 $ 400$400 $600 $ 600$600 $ 600 $ 600 $ 600."— Presentation transcript:

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4 LargerScientistsUnits e- config 101 Is it possible? Potpourri $ 200 $ 200$200 $ 200 $ 200 $400 $ 400$400 $ 400$400 $600 $ 600$600 $ 600 $ 600 $ 600 $800 $ 800$800 $ 800 $ 800 $ 800 $ 1000$1000 $ 1000 $ 1000 $ 1000 $ 1000

5 Smaller So many rules Trends e- config 201 Quantum #More #s $ 400 $ 400 $ 400 $ 400 $ 400 $ 400 $ 800 $ 800 $ 800 $ 800 $ 800 $ 800 $ 1200 $ 1200 $ 1200 $ 1200 $ 1200 $ 1200 $ 1600 $ 1600 $ 1600 $ 1600 $ 1600 $ 1600 $ 2000 $ 2000 $ 2000 $ 2000 $ 2000 $ 2000

6 Final Jeopardy Using the Equations

7 Final Jeopardy 3.77 * 10 -19 J A photon of green light has a wavelength of 525nm. Calculate the energy of the photon (in J).

8 $200 Si Larger Atomic radius of Si or Cl

9 $400 red Larger λ of red light or green light

10 $600 green Larger ν of red light or green light

11 $800 radio Larger λ of radio waves or γ rays

12 $1000 Ionic radius of O 2- Larger atomic radius of O or ionic radius of O 2-

13 $200 Mendeleev

14 $400 Bohr

15 $600 Einstein

16 $800 Schrödinger

17 $1000 Heisenberg

18 $200 m or nm λ

19 $400 Hz or 1/s or s -1 ν

20 $600 J E

21 $800 m/s c

22 $1000 J*s h

23 $200 Li 1s 2 2s 1

24 $400 1s 2 2s 2 2p 2 C

25 $600 Al [Ne] 3s 2 3p 1

26 $800 Br [Ar] 4s 2 3d 10 4p 5

27 $1000 Sg [Rn] 7s 2 5f 14 6d 4

28 $200 Yes 4 3 -2 +½

29 $400 No (m s can only be +½ or -½) 4 3 -2 1

30 $600 Yes 2 0 +½

31 $800 Yes 3 2 -½

32 $1000 No (l values range from 0 to n-1) 2 1 +½

33 $200 anion The name for a negative ion

34 $400 6 S has this # of valence e-

35 $600 2+ Ca ions have this charge

36 $800 Wave-like and particle-like (matter) Light can exhibit a duality of these two properties

37 $1000 Quanta Planck identified that energy comes in packets called what?

38 $400 Ca Smaller electronegativity O or Ca

39 $800 p (3 orientations vs. f with 7 possible orientations) Smaller possible # of orientations p or f shaped orbital

40 $1200 K (require less E to remove outer e- b/c more n, more shielding, further from nucleus) Smaller ionization energy Na or K

41 $1600 n = 5 to n = 6 Smaller energy required to excite an e- from n = 2 to n = 3 or from n = 5 to n = 6

42 $2000 O 2- Smaller ionic radius N 3- or O 2-

43 $400 Pauli Exclusion Principle This tells us no 2 e- in the same atom have the same E (or the same set of quantum numbers)

44 $800 Aufbau Principle This tells us that e- fill orbitals in increasing order of energy

45 $1200 Hund’s Rule This tells us the lowest energy is attained when # of e- with the same spin is maximized

46 $1600 Cr This element is an exception to the rule as it attains greater stability with a ½ filled d subshell and ½ filled s subshell than with its expected 4s 2 3d 4 configuration

47 $2000 Emission spectra / line spectra Rule: We can use this type of spectra to identify an element because no two will be the same

48 $400 More protons, greater nuclear charge This explains why atomic size decreases as we move from left to right across a period

49 $800 More n, greater shielding effect, larger n further away from nucleus This explains why ionic radius increases as we move down a group

50 $1200 Electronegativity This trend tells us an element’s ability to attract e-

51 $1600 Ionization Energy/ Potential This trend tells us the amount of energy required to remove an e- from an atom

52 $2000 Bottom Left This corner of the periodic table includes elements that exhibit the greatest metallic characteristics

53 $400 ns 2 np 6 The general e- config. for a noble gas

54 $800 ns 2 np 2 The general e- config. for an element in Group 4A

55 $1200 [Ne] The noble gas configuration of F - ion

56 $1600 Alkali earth metals An element with the general configuration ns 2 is part of which group (specific name please)

57 $2000 Actinoids An element with the configuration [Rn]7s 2 5f 12 is found in this series of elements

58 $400 l Tells us the shape of an orbital

59 $800 n Describes the energy level or size of an orbital

60 $1200 msms Tells us the spin of an e-

61 $1600 mlml Tells us orientation in space of a given orbital

62 $2000 -3, -2, -1, 0, 1, 2, 3 These are the possible values for m l when l = 3

63 $400 2 Maximum # of e- per orbital

64 $800 8 (2 in the s orbital + 6 in the p orbitals) Maximum # of e- in n = 2

65 $1200 5 # of d orbital orientations

66 $1600 4 (s, p, d, and f) Possible # of subshells in n = 4

67 $2000 8 (2 in 1s + 2 in 2s + 2 in 3s + 2 in 4s) # of e- in the s orbitals of a Ca atom

68 Daily Double Yes 2 0 +½

69 Daily Double n = 5 to n = 6 Energy required to excite an e- from n = 2 to n = 3 or from n = 5 to n = 6

70 Daily Double More n, greater shielding effect, larger n further away from nucleus This explains why ionic radius increases as we move down a group

71 The Jeopardy champion!


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