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Published byCharlotte Fletcher Modified over 9 years ago
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Delta Sigma Modulator For my Mom
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What is Analog? Analog is a quantity that may have any value in a given range Pick a voltage between 0 and 7 volts: 23.45.86.21464321 These are all valid analog voltages
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What is Digital? Digital is a quantity that may only have a defined set of values in a given range The value is defined by a number of bits that may be either 1 or 0 Let’s define the range from 0 to 7 volts by 3 bits 000 = 0 001 = 1 010 = 2 011 = 3 100 = 4 101 = 5 110 = 6 111 = 7
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What is Digital? Pick a voltage between 0 and 7 volts: 23.45.86.21464321 This is the only valid digital voltage (with 3 bits)
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Why use Digital? Noise You are a computer. You need record a voltage. What are the voltages below? Analog Digital (1 or 0) This is a 1This is 5.26383
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So Digital is better? For computers, yes. For noiseless record of data, yes. The world is actually analog We see, hear, smell, taste, feel, analog
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Analog to Digital Converter So we need a way to convert back and forth between analog and digital ADC A to D 2010 DAC D to A 010 2
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Delta Sigma Modulator One type of ADC
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Analog to Digital Converter So we need a way to convert back and forth between analog and digital ADC A to D 2.12 0000111101 011100… DAC D to A 0000111101 011100… 2.12
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Story problem A farmer has a 10 gallon tank of water. It leaks 1 gallon per minute 1 gal/min Water is put in the tank at an unknown rate ? gal/min The tank indicates if it is more than half full The rate of input water is between 0 and 1 gal/min
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Story problem Every minute, the farmer checks the half-full indicator. More than half-full = 1 Less than half-full = 0 If the tank is less than half-full, the farmer adds a gallon to the tank.
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Amount in tank Indicator Amount leaking Amount input Amount added Net change 5.011.00.70.0-0.3 4.701.00.71.00.7 5.411.00.70.0-0.3 5.111.00.70.0-0.3 4.801.00.71.00.7 5.511.00.70.0-0.3 5.211.00.70.0-0.3 4.901.00.71.00.7 5.611.00.70.0-0.3 5.311.00.70.0-0.3 5.011.00.70.0-0.3 4.701.00.71.00.7 Amount in tank Indicator Amount leaking Amount input Amount added Net change
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Story problem Now we have a bit-stream 101101101110 To find the unknown rate of water put into the tank, take the average 1+0+1+1+0+1+1+0+1+1+1+0 12 = 0.67 ≈ 0.7 More iterations will give you more accuracy
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Circuit Equivalent Φ1Φ1 Φ2Φ2 Φ2Φ2 Φ1Φ1 DQ Q
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$ 1 5.0E-6 13.741202019156521 50 5.0 50 159 160 224 192 224 0 159 256 224 288 224 0 159 192 272 192 304 0 159 256 272 256 304 0 w 192 224 192 272 0 w 256 224 256 272 0 w 176 240 240 288 0 w 176 288 272 240 0 c 192 224 256 224 0 1.0E-5 2.4747768778269292 R 256 304 224 336 0 0 40.0 2.5 0.0 a 352 240 464 240 0 5.0 0.0 c 352 160 464 160 0 9.999999999999999E-6 0.1979719629491683 w 464 240 464 160 0 w 352 160 352 224 0 R 352 256 352 304 0 0 40.0 2.5 0.0 w 288 224 352 224 0 R 144 400 96 400 1 2 200.0 2.5 2.5 I 144 400 144 480 0 0.5 w 176 240 144 272 0 w 144 272 144 400 0 w 176 288 176 480 0 w 176 480 144 480 0 a 512 272 656 272 1 5.0 0.0 w 512 256 464 240 0 R 512 288 512 336 0 0 40.0 2.5 0.0 155 720 272 768 272 0 5.0 w 720 272 656 272 0 w 144 400 720 400 0 w 720 304 720 400 0 I 880 544 800 544 0 0.5 w 720 544 608 544 0 w 320 224 352 224 0 w 880 272 880 544 0 w 880 272 944 272 0 R 160 224 80 224 0 4 10.0 2.5 2.5 w 816 272 880 272 0 w 192 304 192 544 0 w 192 544 608 544 0 I 800 544 720 544 0 0.5 o 33 16 0 3 5.0 1.220703125E-5 0 o 34 16 0 2 5.0 0.1 0
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