1. Alexis Mathis Aaron Goode Jessica Anderson

2. Unit Circle

3. Pythagorean theorem  a²+b²=c²  Used to determine the sides of a right triangle

4. Unit chart 030456090120135150180 sin01/22/23/21 2/21/20 cos13/22/21/20-1/2-2/2-3/2 tan03/313und-3-3-3/30 210225240270300315330360 Sin-1/2-2/2-3/2-3/2-2/2-1/20 Cos-3/2-2/2-1/201/22/23/21 tan3/313Und-3-3-3/30

5. Soh-Cah-Toa

6. Right triangle basics  Internal angle=180  Right angle=90  The other two angles must add up to 90  The hypotenuse is the side of the triangle vertical the right angle

7. Solve triangle ABC given side c = 25 cm and side b = 24 cm.  Solution. To find the remaining side a, use the Pythagorean theorem:Pythagorean theorem  a² + 24² = 25² a² = 625 − 576 = 49 a = = 7. Next, to find angle A, we have  cos A = 24 25 = 96 100, on multiplying each term by 4. =.96

8. 030456090120135150180 Sin01/22/23/21 2/21/20 Cos13/22/21/20-1/2-2/2-3/2 Tan03/313und-3-3-3/30 210225240270300315330360 Sin-1/2-2/2-3/2-3/2-2/2-1/20 Cos-3/2-2/2-1/201/22/23/21 tan3/313Und-3-3-3/30

9. inverse  The arcsine, arccosine, and arctangent of relations NotationDefinitionDomain of X ArcsineY=arcsinxX=siny−1 ≤ x ≤ 1 ArccosineY=arccosxX=cosy−1 ≤ x ≤ 1 ArctangentY=arctanxX=tanyAll real numbers

10. Examples: arcsine  Sinx=4/9  X=arcsine4/9  Sinx=8/24  X=arcsine8/24

11. Examples: arccosine  Cosx=3/4  X=arccosine3/4  Cosx=5/7  X=arccosine5/7

12. Examples: Arctangent  Tanx=9/16  X=arctan9/16  Tanx=5/11  X=arctan5/11

13. Using inverse to solve right triangles  a=4  c=6  SinA=4/6  A=arcsin4/6

14. Using inverse..  b=3  c=6  CosA=3/6  A=arccos3/6

15. Word problems  A six-meter-long ladder leans against a building. If the ladder makes an angle of 60° with the ground, how far up the wall does the ladder reach? How far from the wall is the base of the ladder?

16. Word problems  A five-meter-long ladder leans against a wall, with the top of the ladder being four meters above the ground. What is the approximate angle that the ladder makes with the ground?