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Solving Polynomials. Factoring Options 1.GCF Factoring (take-out a common term) 2.Sum or Difference of Cubes 3.Factor by Grouping 4.U Substitution 5.Polynomial.

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Presentation on theme: "Solving Polynomials. Factoring Options 1.GCF Factoring (take-out a common term) 2.Sum or Difference of Cubes 3.Factor by Grouping 4.U Substitution 5.Polynomial."— Presentation transcript:

1 Solving Polynomials

2 Factoring Options 1.GCF Factoring (take-out a common term) 2.Sum or Difference of Cubes 3.Factor by Grouping 4.U Substitution 5.Polynomial Division (to factor out a binomial term)

3 Take-out common monomial (GCF Factoring) 1) 2)

4 Sum or Difference of Cubes 1.Solve 2.Solve

5 Factor by Grouping 3) 4)

6 Solving an Equation of Quadratic Type (“U” Substitution) 5) 6)

7 Synthetic Division Use synthetic division to find the quotient and the remainder when is divided by x – 2. If x – 2 is a factor, then factor the polynomial completely. How can we determine whether x – 2 is a factor?

8 Factor Theorem A polynomial f(x) has a factor x – a iff the remainder is 0.

9 Example 1 Use synthetic division to determine whether x – 1 is a factor of x³ - 1.

10 Example 2 x = -4 is a solution of x³ - 28x – 48 = 0. Use synthetic division to factor and find all remaining solutions.

11 Example 3 x + 3 is a factor of y = 3x³ + 2x² - 19x + 6. Find all the zeros of this polynomial.

12 Rational Roots (Zeros) Test Every rational zero that is possible for a given polynomial can be expressed as the factors of the constant term divided by the factors of the leading coefficient.

13 Example 4 List all possible rational roots for the polynomial y = 10x³ - 15x² - 16x + 12. Then, divide out the factor and solve for all remaining zeros.

14 Example 5 List all possible rational roots for the polynomial y = x³ - 7x – 6. Then, divide out the factor and solve for all remaining zeros.

15 Practice Pg. 213 (53 – 67 odd, 68) Pg. 278 (41, 43, 55, 57, 59)


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