1. © T Madas

2. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8 3(2x – 3y ) =6x–9 y 4(5p + 3 ) =20p+12 3(3f – 2 ) =9f–6 2(4 + 3a ) =8a+6 5(3c – 7 ) =15c–35 3(2p – 5q ) =6p–15q x (x + 3 ) =x 2 +3 u (v + 5 ) =uv+5 n (3 + m ) =3+n m 2x (4 – x ) =8x–2 b (b – c ) =bc–b 5r (1 + t ) =5r+5 y (y 2 – 4 ) = 3 y–4 x u n x 2 2 r t y

3. © T Madas “expand” the following brackets: 3(3b – 4c ) =9b–12c p (p + 6 ) =p 2 +6 x (y + 2 ) =xy+2 v (2 + w ) =2+v w 4t (2 – t ) =8t–4 k (k – h ) =kh–k 3d (3 + d ) =9d+3 x (x 2 – 3 ) = 3 x–3 p x v t 2 2 d 2 x 3e (4 + e ) =12e+3 e 2 3h (4h + k ) =12k+3 hh 2 2b (4a – 5 ) =8b–10 ab x 2 (2x + 1 ) =2 2 +x x 3 3u (2u – 5v ) =6u–15 u 2 v 3y (2x – 7 ) =6y–21 xy t 2 (4t + 3 ) =4 2 +t t 3 p (2p 2 – 5q ) =2p–5 p 3 q 3

4. © T Madas “expand” the following brackets: 3x (5 + x ) =15x+3 x 2 2h (6h + k ) =12k+2 hh 2 3a (3b – 5 ) =9a–15 ab z 2 (5z + 1 ) =5 2 +z z 3 2u (2u – 7v ) =4u–14 u 2 v 4y (2x – 8 ) =8y–32 xy t 2 (6t + 5 ) =6 2 +t t 3 p (7p 2 – 4q ) =7p–4 p 3 q 5 2x 2 (5 + x 2 ) =10x+2 x 4 2h (6h + k ) =12k+2 hh 2 3a (3ab – 1 ) =9a–3 ab n 3 (4n + 1) =4 3 +n n 4 2u 3 (u – 4v ) =2u–8 u 4 v c (2c 3 – 8) =2c–8 c 4 d 4 (3d + 2) =3 4 +d d 5 x 2 (3x 3 – 5) =3x–5 x 5 2 2 2 2 3

5. © T Madas “expand” the following brackets: 1414 (3y3y – )= – y 3 4 y 1212 2 1 8 2323 (2 + )= a 2a 2 1313 a + a 4 3 2 2 9 a 3 (t + )= 3t3t 1313 t + t 3 3 t 2 2 (3 + )= xy 3 2 y + x 2 y 2 x 1212 1 2 x y ( – )= a b ab 1414 1212 1818 1 8 – a 2 b 1 16 a b ( – )= q p pq 1313 1212 1 6 – p 2 q 1 3 p q ( + )= p u 1313 1212 + u 3 v u v 6uv 2 2 3 2 3

6. © T Madas “expand” the following brackets:

7. © T Madas “expand” the following brackets:

8. © T Madas

9. “expand” the following brackets: 3(2a + b ) =6a+3b 2(4x + 3 ) =8x+6 2(3w + 4 ) =6w+8 3(2x – 3y ) =6x–9 y 4(5p + 3 ) =20p+12 3(3f – 2 ) =9f–6 2(4 + 3a ) =8a+6 5(3c – 7 ) =15c–35 3(2p – 5q ) =6p–15q x (x + 3 ) =x 2 +3 u (v + 5 ) =uv+5 n (3 + m ) =3+n m 2x (4 – x ) =8x–2 b (b – c ) =bc–b 5r (1 + t ) =5r+5 y (y 2 – 4 ) = 3 y–4 x u n x 2 2 r t y

10. © T Madas “expand” the following brackets: 3(3b – 4c ) =9b–12c p (p + 6 ) =p 2 +6 x (y + 2 ) =xy+2 v (2 + w ) =2+v w 4t (2 – t ) =8t–4 k (k – h ) =kh–k 3d (3 + d ) =9d+3 x (x 2 – 3 ) = 3 x–3 p x v t 2 2 d 2 x 3e (4 + e ) =12e+3 e 2 3h (4h + k ) =12k+3 hh 2 2b (4a – 5 ) =8b–10 ab x 2 (2x + 1 ) =2 2 +x x 3 3u (2u – 5v ) =6u–15 u 2 v 3y (2x – 7 ) =6y–21 xy t 2 (4t + 3 ) =4 2 +t t 3 p (2p 2 – 5q ) =2p–5 p 3 q 3

11. © T Madas “expand” the following brackets: 3x (5 + x ) =15x+3 x 2 2h (6h + k ) =12k+2 hh 2 3a (3b – 5 ) =9a–15 ab z 2 (5z + 1 ) =5 2 +z z 3 2u (2u – 7v ) =4u–14 u 2 v 4y (2x – 8 ) =8y–32 xy t 2 (6t + 5 ) =6 2 +t t 3 p (7p 2 – 4q ) =7p–4 p 3 q 5 2x 2 (5 + x 2 ) =10x+2 x 4 2h (6h + k ) =12k+2 hh 2 3a (3ab – 1 ) =9a–3 ab n 3 (4n + 1) =4 3 +n n 4 2u 3 (u – 4v ) =2u–8 u 4 v c (2c 3 – 8) =2c–8 c 4 d 4 (3d + 2) =3 4 +d d 5 x 2 (3x 3 – 5) =3x–5 x 5 2 2 2 2 3

12. © T Madas “expand” the following brackets: – y 3 4 1414 (3y3y – )= y 1212 2 1 8 2323 (2 + )= a 2a 2 1313 a + a 4 3 2 2 9 a 3 + t 3 3 t 2 (t + )= 3t3t 1313 t 2 3 2 + x 2 y 2 (3 + )= xy y x 1212 1 2 x y ( – )= a b ab 1414 1212 1818 1 8 – a 2 b 1 16 a b ( – )= q p pq 1313 1212 1 6 – p 2 q 1 3 p q + u 3 v u v ( + )= p u 1313 1212 6uv 2 2 3 2 3

13. © T Madas “expand” the following brackets:

14. © T Madas “expand” the following brackets:

15. © T Madas