1. Lesson 1 MI/Vocab monomial constant Multiply monomials. Simplify expressions involving powers of monomials.

2. Lesson 1 Ex1 Identify Monomials Determine whether each expression is a monomial. Explain your reasoning.

3. A.A B.B C.C D.D Lesson 1 CYP1 Which expression is a monomial? A.x 5 B.3p – 1 C. D.

4. Lesson 3 MI/Vocab polynomial binomial trinomial degree of a monomial degree of a polynomial Find the degree of a polynomial. Arrange the terms of a polynomial in ascending or descending order.

5. Lesson 3 Ex1 Identify Polynomials State whether each expression is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial.

6. A.A B.B C.C D.D Lesson 3 CYP1 A.yes, monomial B.yes, binomial C.yes, trinomial D.none of these A. State whether 3x 2 + 2y + z is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial.

7. A.A B.B C.C D.D Lesson 3 CYP1 A.yes, monomial B.yes, binomial C.yes, trinomial D.none of these B. State whether 4a 2 – b –2 is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial.

8. A.A B.B C.C D.D Lesson 3 CYP1 A.yes, monomial B.yes, binomial C.yes, trinomial D.none of these C. State whether 8r – 5s is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial.

9. A.A B.B C.C D.D Lesson 3 CYP1 A.yes, monomial B.yes, binomial C.yes, trinomial D.none of these D. State whether 3y 5 is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial.

10. Lesson 3 Ex2 Write a Polynomial GEOMETRY Write a polynomial to represent the area of the shaded region. WordsThe area of the shaded region is the area of the rectangle minus the area of the triangle. Variablesarea of the shaded region = A height of rectangle = 2h area of rectangle = b(2h)

11. Lesson 3 Ex2 Write a Polynomial Area of shaded region = rectangle area – triangle area. Answer: Answer Equation

12. Lesson 3 CYP2 1.A 2.B 3.C 4.D A.4r 2 –  r 2 B.  r 2 C.4r 2 D.4r –  r 2 Write a polynomial to represent the area of the green shaded region.

13. Lesson 3 Ex3 Degree of a Polynomial Find the degree of each polynomial. Interactive Lab: Exploring Polynomials

14. 1.A 2.B 3.C 4.D Lesson 3 CYP3 A.3 B.2 C.0 D.1 A. Find the degree of 11ab + 6b +2ac 2 – 7.

15. 1.A 2.B 3.C 4.D Lesson 3 CYP3 A.0 B.2 C.4 D.3 B. Find the degree of 3r 2 + 5r 2 s 2 – s 3.

16. 1.A 2.B 3.C 4.D Lesson 3 CYP3 A.0 B.2 C.7 D.3 C. Find the degree of 2x 5 yz – x 2 yz 3.

17. Lesson 3 Ex4 A. Arrange the terms of 16 + 14x 3 + 2x – x 2 so that the powers of x are in ascending order. 16 + 14x 3 + 2x – x 2 = 16x 0 + 14x 3 + 2x 1 – x 2 x 0 = 1 Answer: = 16 + 2x – x 2 + 14x 3 0 < 1 < 2 < 3 Arrange Polynomials in Ascending Order

18. Lesson 3 Ex4 B. Arrange the terms of 7y 2 + 4x 3 + 2xy 3 – x 2 y 2 so that the powers of x are in ascending order. 7y 2 + 4x 3 + 2xy 3 – x 2 y 2 = 7y 2 + 4x 3 + 2x 1 y 3 – x 2 y 2 x = x 1 Answer: = 7y 2 + 2xy 3 – x 2 y 2 + 4x 3 0 < 1 < 2 < 3 Arrange Polynomials in Ascending Order

19. A.A B.B C.C D.D Lesson 3 CYP4 A.–3x 4 – 2x + 6x 2 + 1 B.1 – 2x + 6x 2 – 3x 4 C.–3x 4 + 6x 2 – 2x + 1 D.1 + 6x 2 – 2x– 3x 4 A. Arrange 6x 2 – 3x 4 – 2x + 1 so that the powers of x are in ascending order.

20. A.A B.B C.C D.D Lesson 3 CYP4 A.4x 3 yz – x 2 + 2xy 4 + 3 B.2xy 4 + 3 + 4x 3 yz – x 2 C.3 + 4x 3 yz – x 2 + 2xy 4 D.3 + 2xy 4 – x 2 + 4x 3 yz B. Arrange 3 + 2xy 4 + 4x 3 yz – x 2 so that the powers of x are in ascending order.

21. Lesson 3 Ex5 A. Arrange 8 + 7x 2 – 12xy 3 – 4x 3 y so that the powers of x are in descending order. 8 + 7x 2 – 12xy 3 – 4x 3 y = 8x 0 + 7x 2 – 12x 1 y 3 – 4x 3 yx 0 = 1 and x = x 1 Answer: = – 4x 3 y + 7x 2 – 12xy 3 + 83 > 2 > 1 > 0 Arrange Polynomials in Descending Order

22. Lesson 3 Ex5 B. Arrange a 4 + ax 2 – 2a 3 xy 3 – 9x 4 y so that the powers of x are in descending order. a 4 + ax 2 – 2a 3 xy 3 – 9x 4 y = a 4 x 0 + a 1 x 2 – 2a 3 x 1 y 3 – 9x 4 y 1 x 0 = 1 and x = x 1 Answer: = – 9x 4 y + ax 2 – 2a 3 xy 3 + a 4 4 > 2 > 1 > 0 Arrange Polynomials in Descending Order

23. A.A B.B C.C D.D Lesson 3 CYP5 A.2 – x 2 + 3x 3 + 4x 4 B.4x 4 + 3x 3 – x 2 + 2 C.–x 2 + 2 + 3x 3 + 4x 4 D.4x 4 + 3x 3 + 2 – x 2 A. Arrange 3x 3 + 4x 4 – x 2 + 2 so that the powers of x are in descending order.

24. A.A B.B C.C D.D Lesson 3 CYP5 A.2y 5 – 7y 3 x 2 – 8x 3 y 2 + 3x 5 B. 3x 5 + 2y 5 – 7y 3 x 2 – 8x 3 y 2 C. 3x 5 – 8x 3 y 2 – 7y 3 x 2 + 2y 5 D. –7y 3 x 2 + 2y 5 – 8x 3 y 2 + 3x 5 B. Arrange 2y 5 – 7y 3 x 2 – 8x 3 y 2 + 3x 5 so that the powers of x are in descending order.

25. Lesson 4 MI/Vocab Add polynomials. Subtract polynomials.

26. Lesson 4 Ex1 Add Polynomials Find (7y 2 + 2y – 3) + (2 – 4y + 5y 2 ). Method 1 Horizontal (7y 2 + 2y – 3) + (2 – 4y + 5y 2 ) = (7y 2 + 5y 2 ) + [2y + (–4y) + [(– 3) + 2]Group like terms = 12y 2 – 2y – 1Add like terms.

27. Lesson 4 Ex1 Add Polynomials Method 2 Vertical Answer: 12y 2 – 2y – 1 7y 2 + 2y – 3 (+) 5y 2 – 4y + 2 Notice that terms are in descending order with like terms aligned. 12y 2 – 2y – 1

28. A.A B.B C.C D.D Lesson 4 CYP1 A.–2x 2 + 5x + 3 B.8x 2 + 6x – 4 C.2x 2 + 5x + 4 D.–15x 2 + 6x – 4 Find (3x 2 + 2x – 1) + (–5x 2 + 3x + 4).

29. Lesson 4 Ex2 Subtract Polynomials Find (6y 2 + 8y 4 – 5y) – (9y 4 – 7y + 2y 2 ). Method 1 Horizontal Subtract 9y 4 – 7y +2y 2 by adding its additive inverse. (6y 2 + 8y 4 – 5y) – (9y 4 – 7y + 2y 2 ) = = (6y 2 + 8y 4 – 5y) + (–9y 4 + 7y – 2y 2 ) The additive inverse of 9y 4 – 7y +2y 2 is –9y 4 + 7y – 2y 2. = [8y 4 + (–9y 4 )] + [6y 2 + (–2y 2 )] + (–5y + 7y) Group like terms. = –y 4 + 4y 2 + 2y

30. Lesson 4 Ex2 Subtract Polynomials Method 2 Vertical Align like terms in columns and subtract by adding the additive inverse. Answer: 4y 2 – y 4 + 2y or –y 4 + 4y 2 + 2y 6y 2 + 8y 4 – 5y (–) 2y 2 + 9y 4 – 7y Add the opposite. 6y 2 + 8y 4 – 5y (+) –2y 2 – 9y 4 + 7y 4y 2 – y 4 + 2y

31. Lesson 4 CYP2 1.A 2.B 3.C 4.D A.2x 2 + 7x 3 – 3x 4 B.x 4 – 2x 3 + x 2 C.x 2 + 8x 3 – 3x 4 D.3x 4 + 2x 3 + x 2 Find (3x 3 + 2x 2 – x 4 ) – (x 2 + 5x 3 – 2x 4 ).

32. Lesson 5 MI/Vocab Find the product of a monomial and a polynomial. Solve equations involving polynomials.

33. Lesson 5 TEKS A.4 The student understands the importance of the skills required to manipulate symbols in order to solve problems and uses the necessary algebraic skills required to simplify algebraic expressions and solve equations and inequalities in problem situations. (A) Find specific function values, simplify polynomial expressions, transform and solve equations, and factor as necessary in problem situations. (B) Use the commutative, associative, and distributive properties to simplify algebraic expressions. Also addresses TEKS A.11(A).

34. Lesson 5 Ex1 Multiply a Polynomial by a Monomial Method 1 Horizontal Find 6y(4y 2 – 9y – 7). 6y(4y 2 – 9y – 7) = 6y(4y 2 ) – 6y(9y) – 6y(7)Distributive Property = 24y 3 – 54y 2 – 42yMultiply.

35. Lesson 5 Ex1 Multiply a Polynomial by a Monomial Method 2 Vertical Answer: 24y 3 – 54y 2 – 42y 4y 2 – 9y – 7 (x) 6yDistributive Property 24y 3 – 54y 2 – 42yMultiply.

36. A.A B.B C.C D.D Lesson 5 CYP1 A.6x 2 + 9x + 15 B.6x 3 + 9x 2 + 15x C.5x 3 + 6x 2 + 8x D.6x 2 + 3x + 5 Find 3x(2x 2 + 3x + 5).

37. Lesson 5 Ex2 Simplify Expressions Simplify 3(2t 2 – 4t – 15) + 6t(5t + 2). 3(2t 2 – 4t – 15) + 6t(5t + 2) = 3(2t 2 ) – 3(4t) – 3(15) + 6t(5t) + 6t(2)Distributive Property = 6t 2 – 12t – 45 + 30t 2 + 12tProduct of Powers = (6t 2 + 30t 2 ) + [(– 12t) + 12t] – 45Commutative and Associative Properties Answer: = 36t 2 – 45Combine like terms.

38. Lesson 5 CYP2 1.A 2.B 3.C 4.D A.4y 2 + 9y + 1 B.8y 2 + 5y – 6 C.20y 2 + 9y + 6 D.28y 2 + 31y – 10 Simplify 5(4y 2 + 5y – 2) + 2y(4y +3).

39. Lesson 5 Ex3 A. ENTERTAINMENT Admission to the Super Fun Amusement Park is $10. Once in the park, super rides are an additional $3 each and regular rides are an additional $2. Sarita goes to the park and rides 15 rides, of which s of those 15 are super rides. Find an expression for how much money Sarita spent at the park. Words VariableIf s = the number of super rides, then 15 – s is the number of regular rides. Let M be the amount of money Sarita spent at the park. Amount of moneyequals admissionplus super rides times $3 per ride plus regular rides times $2 per ride.

40. Lesson 5 Ex3 EquationM = 10 + s ● 3 + (15 – s) ● 2 = 10 +3s + 15(2) – s(2)Distributive Property = 10 + 3s + 30 – 2sSimplify. = 40 + sSimplify. Answer: An expression for the amount of money Sarita spent in the park is 40 + s, where s is the number of super rides she rode.

41. Lesson 5 Ex3 B. Evaluate the expression to find the cost if Sarita rode 9 super rides. 40 + s = 40 + 9s = 9 = 49Add. Answer: Sarita spent $49.

42. 1.A 2.B 3.C 4.D Lesson 5 CYP3 A.70p + 210 B.120p + 70 C.50p + 14,700 D.70p + 120 A. The Fosters own a vacation home that they rent throughout the year. The rental rate during peak season is $120 per day and the rate during the off- peak season is $70 per day. Last year they rented the house 210 days, p of which were during peak season. Find an expression for how much rent the Fosters received.

43. 1.A 2.B 3.C 4.D Lesson 5 CYP3 A.$120,000 B.$21,200 C. $70,000 D.$210,000 B. Evaluate the expression if p is equal to 130.

44. Lesson 5 Ex4 Solve b(12 + b) – 7 = 2b + b(–4 + b). b(12 + b) – 7= 2b + b(–4 + b)Original equation 12b +b 2 – 7= 2b – 4b + b 2 Distributive Property 12b + b 2 – 7= –2b + b 2 Combine like terms. 12b – 7= –2bSubtract b 2 from each side. Polynomials on Both Sides

45. Lesson 5 Ex4 12b = –2b + 7Add 7 to each side. Divide each side by 14. Answer: Polynomials on Both Sides 14b = 7Add 2b to each side.

46. Lesson 5 Ex4 Check b(12 + b) – 7 = 2b + b(–4 + b) Original equation Simplify. Polynomials on Both Sides Multiply. Subtract.

47. A.A B.B C.C D.D Lesson 5 CYP4 Solve x(x + 2) + 2x(x – 3) + 7 = 3x(x – 5) – 12. A. B. C. D.

48. End of Lesson 5

49. Lesson 6 Menu Five-Minute Check (over Lesson 7-5) Main Ideas and Vocabulary Targeted TEKS Example 1: The Distributive Property Key Concept: FOIL Method Example 2: FOIL Method Example 3: FOIL Method Example 4: The Distributive Property

50. Lesson 6 MI/Vocab FOIL method Multiply two binomials by using the FOIL method. Multiply two polynomials by using the Distributive Property.

51. Lesson 6 TEKS A.4 The student understands the importance of the skills required to manipulate symbols in order to solve problems and uses the necessary algebraic skills required to simplify algebraic expressions and solve equations and inequalities in problem situations. (A) Find specific function values, simplify polynomial expressions, transform and solve equations, and factor as necessary in problem situations. (B) Use the commutative, associative, and distributive properties to simplify algebraic expressions. Also addresses TEKS A.11(A).

52. Lesson 6 Ex1 The Distributive Property Find (y + 8)(y – 4). Method 1 Vertical Multiply by –4. y + 8 (×) y – 4 –4y – 32–4(y + 8) = –4y – 32 Multiply by y. y 2 + 8yy(y + 8) = y 2 + 8y Combine like terms. y 2 + 4y – 32 y + 8 (×) y – 4

53. Lesson 6 Ex1 The Distributive Property Method 2 Horizontal (y + 8)(y – 4) = y(y – 4) + 8(y –4)Distributive Property = y(y) – y(4) + 8(y) – 8(4)Distributive Property = y 2 – 4y + 8y – 32Multiply. = y 2 + 4y – 32Combine like terms. Answer: y 2 + 4y – 32

54. A.A B.B C.C D.D Lesson 6 CYP1 A.c 2 – 6c + 8 B.c 2 – 4c – 8 C.c 2 – 2c + 8 D.c 2 – 2c – 8 Find (c + 2)(c – 4).

55. Key Concept 7-6a

56. Lesson 6 Ex2 FOIL Method A. Find (z – 6)(z – 12). (z – 6)(z – 12)= z(z) Answer: z 2 – 18z + 72 F O I L (z – 6)(z – 12)= z(z) + z(–12)(z – 6)(z – 12)= z(z) + z(–12) + (–6)z + (–6)(–12)(z – 6)(z – 12)= z(z) + z(–12) + (–6)z = z 2 – 12z – 6z + 72Multiply. = z 2 – 18z + 72Combine like terms. F (z – 6)(z – 12) OIL

57. Lesson 6 Ex2 FOIL Method B. Find (5x – 4)(2x + 8). (5x – 4)(2x + 8) Answer: = 10x 2 + 32x – 32Combine like terms. = (5x)(2x) + (5x)(8) + (–4)(2x) + (–4)(8) F OIL = 10x 2 + 40x – 8x – 32Multiply.

58. Lesson 6 CYP2 1.A 2.B 3.C 4.D A.x 2 + x – 6 B.x 2 – x – 6 C.x 2 + x + 6 D.x 2 + x + 5 A. Find (x + 2)(x – 3).

59. Lesson 6 CYP2 1.A 2.B 3.C 4.D A.5x 2 – 8x + 30 B.6x 2 + 28x – 1 C.6x 2 – 8x – 30 D.6x – 30 B. Find (3x + 5)(2x – 6).

60. Lesson 6 Ex3 FOIL Method GEOMETRY The area A of a triangle is one half the height h times the base b. Write an expression for the area of the triangle. Explore Identify the height and the base. h = x – 7 b = 6x + 7 Plan Now write and apply the formula. Area equals one half height times base. A = h ● b

61. Lesson 6 Ex3 FOIL Method Original formula Substitution FOIL method Multiply.

62. Lesson 6 Ex3 FOIL Method Combine like terms. Answer: The area of the triangle is 3x 2 – 19x – 14 square units. Distributive Property

63. 1.A 2.B 3.C 4.D Lesson 6 CYP3 A.7x + 3 units 2 B.12x 2 + 11x + 2 units 2 C.12x 2 + 8x + 2 units 2 D.7x 2 + 11x + 3 units 2 GEOMETRY The area of a rectangle is the measure of the base times the height. Write an expression for the area of the rectangle.

64. Lesson 6 Ex4 A. Find (3a + 4)(a 2 – 12a + 1). (3a + 4)(a 2 – 12a + 1) = 3a(a 2 – 12a + 1) + 4(a 2 – 12a + 1)Distributive Property = 3a 3 – 36a 2 + 3a + 4a 2 – 48a + 4Distributive Property Answer: = 3a 3 – 32a 2 – 45a + 4Combine like terms. The Distributive Property

65. Lesson 6 Ex4 B. Find (2b 2 + 7b + 9)(b 2 + 3b – 1). (2b 2 + 7b + 9)(b 2 + 3b – 1) = (2b 2 )(b 2 + 3b – 1)+ 7b(b 2 + 3b – 1) + 9(b 2 + 3b – 1) Distributive Property = (2b 4 + 6b 3 – 2b 2 + 7b 3 + 21b 2 – 7b + 9b 2 + 27b – 9) Distributive Property Answer: = 2b 4 + 13b 3 + 28b 2 + 20b – 9Combine like terms. The Distributive Property

66. A.A B.B C.C D.D Lesson 6 CYP4 A.12z 3 + 9z 2 + 15z B.8z 2 + 6z + 10 C.12z 3 + z 2 + 9z + 10 D.12z 3 + 17z 2 + 21z + 10 A. Find (3z + 2)(4z 2 + 3z + 5).

67. A.A B.B C.C D.D Lesson 6 CYP4 A.12x 4 – 9x 3 – 6x 2 B.7x 3 – x – 1 C.12x 4 – x 3 – 8x 2 – 7x – 2 D.–x 2 + 5x + 3 B. Find (3x 2 + 2x + 1)(4x 2 – 3x – 2).

68. End of Lesson 6

69. Lesson 7 Menu Five-Minute Check (over Lesson 7-6) Main Ideas and Vocabulary Targeted TEKS Key Concept: Square of a Sum Example 1: Square of a Sum Key Concept: Square of a Difference Example 2: Square of a Difference Example 3: Real-World Example Key Concept: Product of a Sum and a Difference Example 4: Product of a Sum and a Difference

70. Lesson 7 MI/Vocab difference of squares Find squares of sums and differences. Find the product of a sum and a difference.

71. Lesson 7 TEKS A.4 The student understands the importance of the skills required to manipulate symbols in order to solve problems and uses the necessary algebraic skills required to simplify algebraic expressions and solve equations and inequalities in problem situations. (A) Find specific function values, simplify polynomial expressions, transform and solve equations, and factor as necessary in problem situations. (B) Use the commutative, associative, and distributive properties to simplify algebraic expressions. Also addresses TEKS A.11(A).

72. Key Concept 7-7a

73. Lesson 7 Ex1 Square of a Sum Find (7z + 2) 2. (a + b) 2 = a 2 + 2ab + b 2 (7z + 2) 2 = (7z) 2 + 2(7z)(2) + (2) 2 a = 7z and b = 2 Answer: = 49z 2 + 28z + 4Simplify.

74. A.A B.B C.C D.D Lesson 7 CYP1 A.9x 2 + 4 B.9x 2 + 6x + 4 C.9x + 4 D.9x 2 + 12x + 4 Find (3x + 2) 2

75. Key Concept 7-7b

76. Lesson 7 Ex2 Square of a Difference Find (3c – 4) 2. (a – b) 2 = a 2 – 2ab + b 2 (3c – 4) 2 = (3c) 2 – 2(3c)(4) + (4) 2 a = 3c and b = 4 Answer: = 9c 2 – 24c + 16Simplify.

77. Lesson 7 CYP2 1.A 2.B 3.C 4.D A.9m 2 + 4 B.9m 2 – 4 C.9m 2 – 6m + 4 D.9m 2 – 12m + 4 Find (3m – 2) 2.

78. Lesson 7 Ex3 GEOMETRY Write an expression that represents the area of a square that has a side length of 2x + 12 units. The formula for the area of a square is A = s 2. Answer: The area of the square is 4x 2 + 48x + 144 square units. A = s 2 Area of a square A = (2x + 12) 2 s = (2x + 12) A = (2x) 2 + 2(2x)(12) + (12) 2 a = 2x and b = 12 A = 4x 2 + 48x + 144Simplify.

79. 1.A 2.B 3.C 4.D Lesson 7 CYP3 A.9x 2 – 24x + 16 units 2 B.9x 2 + 16 units 2 C.9x 2 – 16 units 2 D.9x 2 – 12x + 16 units 2 GEOMETRY Write an expression that represents the area of a square that has a side length of (3x – 4) units.

80. Key Concept 7-7c Animation: Product of a Sum and a Difference

81. Lesson 7 Ex4 Find (9d + 4)(9d – 4). (a + b)(a – b) = a 2 – b 2 (9d + 4)(9d – 4) = (9d) 2 – (4) 2 a = 9d and b = 4 Answer: = 81d 2 – 16Simplify. Product of a Sum and a Difference

82. A.A B.B C.C D.D Lesson 7 CYP4 A.9y 2 + 4 B.6y 2 – 4 C.6y 2 + 4 D.9y 2 – 4 Find (3y + 2)(3y – 2).

83. End of Lesson 7

84. CR Menu Five-Minute Checks Image Bank Math Tools Animation Menu Exploring Polynomials Multiplying and Dividing Monomials Polynomials

85. 5Min Menu Lesson 7-1Lesson 7-1(over Chapter 6) Lesson 7-2Lesson 7-2(over Lesson 7-1) Lesson 7-3Lesson 7-3(over Lesson 7-2) Lesson 7-4Lesson 7-4(over Lesson 7-3) Lesson 7-5Lesson 7-5(over Lesson 7-4) Lesson 7-6Lesson 7-6(over Lesson 7-5) Lesson 7-7Lesson 7-7(over Lesson 7-6)

86. IB 1 To use the images that are on the following three slides in your own presentation: 1.Exit this presentation. 2.Open a chapter presentation using a full installation of Microsoft ® PowerPoint ® in editing mode and scroll to the Image Bank slides. 3.Select an image, copy it, and paste it into your presentation.

87. IB 2

88. IB 3

89. IB 4

90. Animation Menu 7-47-4 Use Algebra TilesUse Algebra Tiles 7-67-6 Multiplying PolynomialsMultiplying Polynomials 7-7Product of a Sum and a Difference

91. Animation 1

92. Animation 2

93. Animation 3

94. A.A B.B C.C D.D 5Min 1-1 A.{x | x < –7} B.{x | x < 7} C.{x | x > –7} D.{x | x > 7} Solve the inequality –7x < –9x + 14. (over Chapter 6)

95. 5Min 1-2 1.A 2.B 3.C 4.D (over Chapter 6) A. B. C.{w | w –15} D.{w | w 15} Solve the inequality

96. 1.A 2.B 3.C 4.D 5Min 1-3 Which of the following options shows the solution set of the inequality | 3a – 2 | < 4, and a graph of the solution set? (over Chapter 6) A. B. C. D.

97. A.A B.B C.C D.D 5Min 1-4 A.5n – 10 < 10; n < 4 B.5n – 10 > 10; n > 4 C.10 – 5n > 10; n > 4 D.10 – 5n < 10; n < 4 Write an inequality for the statement, and then solve. Ten less than five times a number n is greater than ten. (over Chapter 6)

98. 5Min 1-5 1.A 2.B 3.C 4.D A.16 nickels B.14 nickels C.12 nickels D.10 nickels Lori had a quarter and some nickels in her pocket, but she had less than $0.80. What is the greatest number of nickels she could have had? (over Chapter 6)

99. 1.A 2.B 3.C 4.D 5Min 1-6 A.(3, 3) B.(–3, 3) C.(4, 5) D.(2, –3) (over Chapter 6) Which point satisfies the system of inequalities x ≤ 3, y > x, and y ≥ 3?

100. A.A B.B C.C D.D 5Min 2-1 A.Yes; the expression involves only one variable. B.Yes; the expression is the product of a number and variables. C.No; the expression is the product of a number and variables. D.No; the expression involves more than one term. Which option states whether the expression –5x 2 is a monomial, and provides a reasonable explanation? (over Lesson 7-1)

101. 5Min 2-2 1.A 2.B 3.C 4.D A.Yes; The expression involves variables and no numbers. B.Yes; The expression is the difference between two powers of variables. C.No; The expression does not involve numbers D.No; The expression is the difference between two powers of variables. Which option states whether the expression x 3 – y 3 is a monomial, and provides a reasonable explanation? (over Lesson 7-1)

102. 1.A 2.B 3.C 4.D 5Min 2-3 A.–3a 5 b 6 B.–3a 4 b 8 C.–3a 3 b 6 D.–3a 4 b 6 Simplify (3ab 4 ) × (–a 4 b 2 ). (over Lesson 7-1)

103. A.A B.B C.C D.D 5Min 2-4 A.2x 10 y 8 B.2x 25 y 16 C.4x 25 y 16 D.4x 10 y 8 Simplify (2x 5 y 4 ) 2. (over Lesson 7-1)

104. 5Min 2-5 1.A 2.B 3.C 4.D A.6n 5 B.6n 3 C.5n 5 D.5n 6 Find the area of the parallelogram shown in the image. (over Lesson 7-1)

105. 1.A 2.B 3.C 4.D 5Min 2-6 A.2.375 B.12.5 C.13.5 D.13.8 What is the value of 4x 3 – 1 when x = 1.5? (over Lesson 7-1)

106. A.A B.B C.C D.D 5Min 3-1 (over Lesson 7-2) Simplify. A. B. C.7 D.49

107. 5Min 3-2 1.A 2.B 3.C 4.D (over Lesson 7-2). Assume that the denominator is not zero. A. B. C. D.

108. 1.A 2.B 3.C 4.D 5Min 3-3 (over Lesson 7-2) A. B. C. D.

109. A.A B.B C.C D.D 5Min 3-4 (over Lesson 7-2) A. B. C. D.

110. 5Min 3-5 1.A 2.B 3.C 4.D A.2 to 1 B.2 to 3 C.1 to 1 D.1 to 2 Refer to the figure. Find the ratio of the area of the square to the area of the triangle. (over Lesson 7-2)

111. 1.A 2.B 3.C 4.D 5Min 3-6 Which expression has the least value? (over Lesson 7-2) A. B. C. D.

112. A.A B.B C.C D.D 5Min 4-1 A.no B.yes; monomial C.yes; binomial D.yes; trinomial State whether the expression –8 is a polynomial. If the expression is a polynomial, identify it as a monomial, a binomial, or a trinomial. (over Lesson 7-3)

113. 5Min 4-2 1.A 2.B 3.C 4.D A.no B.yes; monomial C.yes; binomial D.yes; trinomial (over Lesson 7-3) State whether the expression is a polynomial. If the expression is a polynomial, identify it as a monomial, a binomial, or a trinomial.

114. 1.A 2.B 3.C 4.D 5Min 4-3 Refer to the figure. Write a polynomial to represent the area of the shaded region. (over Lesson 7-3) A.x 2 ab B. C. D. x 2 – ab

115. A.A B.B C.C D.D 5Min 4-4 A.2 B.3 C.4 D.5 What is the degree of the polynomial 5ab 3 + 4a 2 b + 3b 5 – 2? (over Lesson 7-3)

116. 5Min 4-5 1.A 2.B 3.C 4.D A.M > N B.N > M C.M = N = 0 D.M = N = 1 If 0 < x < 1, M = x 3 – x 2 + 1, and N = x 2 – x 3 + 1, which statement is true? (over Lesson 7-3)

117. A.A B.B C.C D.D 5Min 5-1 A.2a 2 – 3a + 7b 2 B.2a 2 + 3a + 8b 2 C.2a 2 – 9a + 8b 2 D.2a 2 + 3a + 7b 2 Simplify (6a + 7b 2 ) + (2a 2 – 3a + b 2 ). (over Lesson 7-4)

118. 5Min 5-2 1.A 2.B 3.C 4.D A.5x 2 – 4x – 3 B.5x 2 + 4x – 3 C.4x 2 + 4x – 3 D.4x 2 – 4x – 3 Simplify (5x 2 – 3) – (x 2 + 4x). (over Lesson 7-4)

119. 1.A 2.B 3.C 4.D 5Min 5-3 A.3x 2 + 11x – 10 B.3x 2 – 5x – 6 C.3x 2 – 5x – 10 D.3x 2 + 10x – 11 Simplify (6x 2 + 2x – 9) – (3x 2 – 8x + 2) + (x + 1). (over Lesson 7-4)

120. A.A B.B C.C D.D 5Min 5-4 A.5x 2 + x + 3 B.x 2 + 3x – 4y – 3 C.x 2 + x + 3 D.5x 2 + 3x – 2y + 3 Refer to the figure. If P is the perimeter of the triangle and the measures of the two sides are given, find the measure of the third side of the triangle. (over Lesson 7-4)

121. 5Min 5-5 1.A 2.B 3.C 4.D A.5x 2 + 12x + 9 B.3x 2 – 2x + 13 C.–3x 2 + 2x – 9 D.–5x 2 – 12x + 13 Which of the following polynomials was added to x 2 + 7x – 2 to get a sum of –4x 2 – 5x + 11? (over Lesson 7-4)

122. A.A B.B C.C D.D 5Min 6-1 A.–3w 3 – 21w – 27 B.–3w 3 – 21w + 27 C.–3w 3 + 21w 2 – 27w D.–3w 3 – 21w 2 + 27w Find the product. –3w(w 2 + 7w – 9) (over Lesson 7-5)

123. 5Min 6-2 1.A 2.B 3.C 4.D (over Lesson 7-5) A. B. C. D. Find the product.

124. 1.A 2.B 3.C 4.D 5Min 6-3 A.15a 2 b – 7ab + 1 B.15a 3 b – 7ab + 1 C.15a 3 b + 12a 2 b + 4ab + 2a D.15a 3 b – 3a 2 b – 4ab + 2a Simplify 3ab(5a 2 – a – 2) + 2a(b + 1). (over Lesson 7-5)

125. A.A B.B C.C D.D 5Min 6-4 Solve the equation 3(2c – 3) – 1 = –4(2c +1) + 8. (over Lesson 7-5) A. B.–1 C.1 D.

126. 5Min 6-5 1.A 2.B 3.C 4.D Solve the equation 5(9w + 2) = 3(8w – 7) + 17. (over Lesson 7-5) A. B. C. D.

127. 1.A 2.B 3.C 4.D 5Min 6-6 A.10x(x + 1) B.100x(x + 1) C.100x 2 + 1 D.10x(10x + 1) If x is any whole number, which of the following is an expression for the product of two consecutive multiples of 10? (over Lesson 7-5)

128. A.A B.B C.C D.D 5Min 7-1 A.a 2 + 3a – 18 B.a 2 – 3a – 18 C.a 2 – 3a D.a 2 – 18 Find the product of (a + 6)(a – 3). (over Lesson 7-6)

129. 5Min 7-2 1.A 2.B 3.C 4.D A.6w 2 + 35 B.6w 2 + 29w C.6w 2 + 29w + 35 D.6w 2 + 15w + 49 Find the product of (3w + 7)(2w + 5). (over Lesson 7-6)

130. 1.A 2.B 3.C 4.D 5Min 7-3 A.25b 3 – 19b – 6 B.25b 3 – 19b + 6 C.25b 3 – b + 6 D.25b 3 + 15b 2 – 10b – 3 Find the product of (5b – 3)(5b 2 + 3b – 2). (over Lesson 7-6)

131. A.A B.B C.C D.D 5Min 7-4 Write an expression to represent the area of the figure. (over Lesson 7-6) A.3a 3 – 9a 2 + 2a – 3 units 2 B.3a 3 – 9a 2 + 2a units 2 C.6a 3 – 9a 2 + 2a – 3 units 2 D.6a 3 – 3 units 2

132. 5Min 7-5 1.A 2.B 3.C 4.D Write an expression to represent the area of the figure. (over Lesson 7-6) A.48k 3 + 46k 2 + k + 5 units 2 B.48k 3 + 34k 2 – k + 5 units 2 C.48k 3 + 39k 2 + k + 5 units 2 D.48k 3 + 34k 2 + k + 5 units 2

133. 1.A 2.B 3.C 4.D 5Min 7-6 A.3 B.3x – 5 C.6x + 3 D.5 Simplify (x + 2)(x + 2) – (x – 1)(x – 1). (over Lesson 7-6)

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