1. 12.2 – Surface Area of Prisms and Cones

2. Cylinder: Prism with circular bases

3. Surface area: Area of each face of a solid

4. Lateral area: Area of each lateral face

5. Right Prism: Each lateral edge is perpendicular to both bases

6. Oblique Prism: Each lateral edge is NOT perpendicular to both bases

7. Net: Two-dimensional representation of a solid

8. Surface Area of a Right Prism: SA = 2B + PH B = area of one base P = Perimeter of one base H = Height of the prism H (distance from base to base)

9. Surface Area of a Right Cylinder: H SA = 2B + PH

10. 1. Name the solid that can be formed by the net. Cylinder

11. 1. Name the solid that can be formed by the net. Triangular prism

12. 1. Name the solid that can be formed by the net. rectangular prism

13. 2. Find the surface area of the right solid. SA = 2B + PH SA = 2(30) + (22)(7) B = bh B = (5)(6) B = 30 P = 5 + 6 + 5 + 6 P = 22 SA = 60 + 154 SA = 214m2m2

14. 2. Find the surface area of the right solid. SA = 2B + PH SA = 2(30) + (30)(10) P = 5 + 12 + 13 P = 30 SA = 60 + 40 SA = 100cm 2 c 2 = a 2 + b 2 c 2 = (5) 2 + (12) 2 c 2 = 25 + 144 c 2 = 169 c = 13

15. 2. Find the surface area of the right solid. cm 2

16. 2. Find the surface area of the right solid. in 2 144in

17. 3. Solve for x, given the surface area. SA = 2B + PH 142 = 2(5x) + (2x + 10)(7) B = bh B = 5x P = 5 + x + 5 + x P = 2x + 10 142 = 10x + 14x + 70 142 = 24x + 70 72 = 24x 3ft = x

18. 3. Solve for x, given the surface area. -32π 8π8π8π8π