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Published byDaniella Porter Modified over 8 years ago
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1 A framework for eager encoding Daniel Kroening ETH, Switzerland Ofer Strichman Technion, Israel (Executive summary) (submitted to: Formal Aspects of Computing)
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2 A generic framework for reducing decidable logics to propositional logic (beyond NP). Instantiating the framework for a specific logic L, requires a deductive system for L that meets several criteria. Linear arithmetic, EUF, arrays etc all have it.
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3 A proof rule: A proof step: (Rule, Antecedent, Proposition) Definition (Proof-step Constraint): let A 1 …A k be the Antecedents and p the Proposition of step. Then: Boolean encoding
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4 A proof P =(s 1,…, s n ) is a set of Proof Steps, …in which the Antecedence relation is acyclic The Proof Constraint c(P) induced by P is the conjunction of the constraints induced by its steps: PC(P)PC(P)
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5 Propositional skeleton: Theorem 1: For every formula and any sound proof P, is satisfiable ) sk Æ c(P) is satisfiable.
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6 Complete proofs Definition (Complete proofs): A proof P is called complete with respect to if
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7 Notation: A – assumption, B – a proposition. denotes: P proves B from A. Let be an unsatisfiable formula Theorem 2: A proof P is complete with respect to if for every full assignment TL( ): Theory Literals corresponding to Sufficient condition for completeness #1 Not constructive!
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8 Projection of a variable x: a set of proof steps that eliminate x and maintains satisfiability. Strong projection of a variable x: a projection of x that maintains : The projected consequences from each minimal unsatisfiable core of literals is unsatisfiable.
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9 Consider the formula Example – strong projection Both sub-formulas are unsatisfiable and do not contain x 1. Now strongly project x 1 : U1U1 U2U2
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10 Let C be a conjunction of ’s literals. A proof construction procedure: eliminate all variables in C through strong projection. Theorem 3: The constructed proof is ‘complete’ for .
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11 Goal: for a given logic L, Find a strong projection procedure. Construct P Generate c(P) Check sk Æ c(P)
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12 C : x 1 - x 2 < 0, x 1 - x 3 < 0, -x 1 + 2x 3 + x 2 < 0, -x 3 < -1 Example: Disjunctive Linear Arithmetic [S02] A proof P by (Strong) projection: e 1 e 2 e 3 e 4 e 1 e 3 e 5 4. Solve ’ = sk Æ c(P) x1:x1: e 2 e 3 e 6 2 x 3 < 0, e5 e5 x 3 + x 2 < 0 e6 e6 e 4 e 5 false x3:x3:
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13 What now ? It is left to show a strong projection method for each logic we are interested in integrating. Current eager procedures are far too wasteful. Need to find better ones.
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14 Optimizations Optimizations that were previously published in the ‘eager encoding’ series can all be interpreted in this framework. Conjunction Matrices Simplifications and early detection Cross-theory learning
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15 Cross-theory learning C (T1): C (T2): From T1 we learn z 1 = z 2 which we propagate to T2 In T2 we get a contradiction on: z 1 > 2, z 2 =1, z 1 = z 2 This results in a conflict clause: Which represents cross-theory learning
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16 Projection (by example) (Starting from a conjunction of literals) Indeed, x 1 var ( x 4 > x 4 ) ’ = (x 2 > x 3 ) Æ (x 4 > x 4 ) is equisatisfiable to
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17 : ( x 1 - x 2 < 0) (x 1 - x 3 < 0) ((-x 1 + 2x 3 + x 2 < 0) (-x 3 < -1)) c : ( x 1 - x 2 < 0) (x 1 - x 3 < 0) (-x 1 + 2x 3 + x 2 < 0) Æ (-x 3 < -1) : ( x 1, x 2, x 3 ) Choose x 1 : ( x 2, x 3 ) Strong-project: P ’={(R, (2 x 3 · 0), { ( x 1 - x 2 < 0), (-x 1 + 2x 3 + x 2 < 0)}, (R, (x 2 + x 3 · 0), { ( x 1 - x 2 < 0), (-x 1 + 2x 3 + x 2 < 0)}} c : (2 x 3 · 0) (x 2 + x 3 · 0) (-x 3 < -1)
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18 Example c(step):= e(x=5) Æ e(:x¸ 0) ! e(:5 ¸ 0) A new variable
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19 Prove validity of x 5 Ç x ¸ 0 by using atoms only Example
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20 Example (cont’d) : sk Æ c(P’) is unsatisfiable hence is valid
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21 - an unsatisfiable formula. A - the set of minimal assignments that satisfy sk. A proof P is complete with respect to if 8 2 A, TL( ): Theory Literals corresponding to For a partial assignment s.t. ² , is minimal if 8v. nv 2 Sufficient condition for completeness #2
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22 - an unsatisfiable formula A - the set of minimal assignments that satisfy sk. A proof P is complete with respect to if 8 2 A, for some unsatisfiable core TL uc ( ) µ TL( ) Sufficient condition for completeness #3
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23 Proof-graph of P A A B P proves B using A: A,B: sets of propositions
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