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Published byColin Bradford Modified over 9 years ago
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The Derivative as a Rate of Change
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In Alg I and Alg II you used the slope of a line to estimate the rate of change of a function with respect to its independent variable. We know this would be the average rate of change over an interval.
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We now know that if we take the derivative of any function at a point, it would give us the rate of change of that function for that value, that particular item, or a particular moment in time.
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Area of a Circle: r The rate of change in the area with respect to the radius. Units would be
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r Ex: As the radius of a circle changes, so does the area. Find the rate of change in the area of a circle when its radius is 8cm.
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We will focus on some familiar rates having to do with motion.
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There are a lot of terms that we need to define.
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Suppose the position of a moving particle is given in the form of a function of time, s(t). (Note: s is not my choice, it is the typical letter used for these problems.)
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For our purposes (and abilities at this point) we say that the particle is moving along a number line.
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If s(2)=5 then the particle is at 5 when t=2. If s(4)=-6 then the particle is at -6 when t=4. 0
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Whenever the term initial is used, it means when t=0. Ex. The initial position of the particle would be found by s(0).
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Displacement: the change in the position over an interval of time
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What would a displacement of -5 mean? The moving particle ended up 5 units to the left of where it started.
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What would a displacement of 0 mean? It does not necessarily mean that the particle didn’t move. It just means that it ended up where it started.
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IB Only: “Displacement function”: is just the position function.
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Velocity: The rate of change in the position with respect to time
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Average Velocity: The rate of change in the position over an interval of time
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Finding Average Velocity: is just like finding the slope of the secant line. Average velocity doesn’t tell you much about the particle’s movements between
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Instantaneous Velocity: The rate of change in the position at a given moment in time:
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A positive velocity means the particle is moving forward. A negative velocity means that the particle is moving backwards.
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What would a velocity of 0 mean? That the particle is not moving, or is“at rest”.
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What must happen before a particle can change directions? The particle must stop, that is, its velocity must reach zero.
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The Units of Velocity: The notation is a great reminder of the units. Whether average velocity or instantaneous:
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Speed: (The rate of change in position with respect to time, but without direction) Note: When a question asks “how fast”, it is asking for the speed. This can be average or instantaneous velocity
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Acceleration: The rate of change in velocity with respect to time
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Position function: Velocity function: Acceleration function:
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The Units of Acceleration: The notation is a great reminder of the units: If the units of both times are the same
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Just like velocity, acceleration can be positive, negative or zero.
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What would a positive acceleration mean? The velocity is increasing. Example: Think of pressing on the accelerator.
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What would a negative acceleration mean? The velocity is decreasing. Example: Think of letting up on the accelerator.
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What would a zero acceleration mean? The velocity is constant. Example: Think of “cruise control”.
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Be careful about using terms like “speeding up” and “slowing down” These are specifically defined.
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t s(t) velocity is + Acceleration is – = Slowing down
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t s(t) velocity is + Acceleration is + = Speeding Up
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t s(t) velocity is – Acceleration is – = Speeding Up
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t s(t) velocity is - Acceleration is + = Slowing down
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If the velocity and the acceleration of a particle at a given time, t: A. Are the same sign, then the particle is speeding up. B. are opposite signs, then the particle is s ss slowing down.
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Example: Given a particle moving along a line. Its position in units on the line at t sec (t>0) is given by:
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What is the particle’s initial position?
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Find a function for the velocity of the particle at any time t?
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Find the particle’s displacement from t=0 to t=3?
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Find the particle’s average velocity from t=0 to t=3?
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What is the particle’s initial velocity?
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Find a function for the acceleration of the particle at any time t.
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Find the speed of the function at t=3?
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When is the particle “at rest”? Only one of those times is positive. At t = 3.2 sec approx. the particle stops
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Is the particle speeding up or slowing down at t=4. Both are same sign, therefore speeding up
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t=0 S=0 t=1 S= -14 t=3 S= -36 t=3.2 S= -36.4 t=6, S= 36
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Concept Questions!
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In the next slide we are given the graph of a position function, s(t), for a particle in motion on a number line at time t in seconds.
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ca f e d b S(t) t Describe the initial position of the particle relative to the origin? To the left of the origin
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ca f e d b S(t) t When is the particle at the origin? t=a, t=c, t=e
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ca f e d b S(t) t When is the particle moving forward? (0,b) (d,f)
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ca f e d b S(t) t When is the particle moving backward? (,b,d,)
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ca f e d b S(t) t When is the particle at rest? t=b, t=d
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ca f e d b S(t) t When is the particle to the right of the origin? (a,c) (e,f)
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ca f e d b S(t) t At t=c is the acceleration positive or negative ? positive
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ca f e d b S(t) t At t=c is the particle speeding up or slowing down? Slowing down
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ca f e d b S(t) t At t=e is the acceleration positive or negative ? positive
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ca f e d b S(t) t At t=e is the particle speeding up or slowing down? Speeding Up
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In the next slide we are given the graph of the velocity function, v(t), for a particle in motion at time t in seconds.
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ca f e d b v(t) t When is the particle moving forward? (a,c) (e,f)
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ca f e d b v(t) t When is the particle moving backward? (0,a) (c,e)
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ca f e d b v(t) t When is the particle at rest? t=a, t=c, t=e
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ca f e d b v(t) t When is the acceleration of the particle positive? (0,b) (d,f)
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ca f e d b v(t) t When is the acceleration of the particle negative? (b,d)
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ca f e d b v(t) t At t=g is the particle speeding up or slowing down ? Slowing down g
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ca f e d b v(t) t At t=g is the particle speeding up or slowing down? Speeding up g
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ca f e d b v(t) t At t=g is the particle speeding up or slowing down? Speeding up g
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ca f e d b v(t) t When is the acceleration zero ? t=b, t=d
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